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Change core::iter::Fuse
's Default
impl to do what its docs say it does
#140985
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IMO this is pointing out an arbitrary case that is in no way surprising (at least not to someone unfamiliar with the implementation history). I think what would be more helpful is to say that this function is equivalent to
IteratorType::default().fused()
.Uh oh!
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Not mentioning non-empty
I::default()
at all would IMO make the doctest seem like a non-sequitur (and the doctest should remain so this change doesn't get accidentally undone later), so I think it should still be mentioned as an aside.I changed this to say
with a footnote that the equivalence assumes
I::fuse
is not overridden. Does that sound good?(Github is being wierd for me and not updating properly: the sentence I changed this from was "Note that if
I
's default value is not an empty iterator, then this will not be an empty iterator.")