Omit in 3.5 breaking Discriminated Unions

[aczekajski]

TypeScript Version: 3.5.0-rc, 3.5.0-dev.20190521

Search Terms: discriminated union omit, tagged union omit

Code

// discriminated union
type Union =
    | { type: 'A', a: 'a', c: string }
    | { type: 'B', b: 'b', c: string };

// various Omit definitions
type Omit<T, K extends keyof any> = Pick<T, Exclude<keyof T, K>>; // new omit copied from TS 3.5
type OmitBetter<T, K extends keyof any> = T extends any ? Pick<T, Exclude<keyof T, K>> : never;
type OmitBetterStrict<T, K extends keyof T> = T extends any ? Pick<T, Exclude<keyof T, K>> : never;

// Omit use-cases with Discriminated Union (DU)
type UnionMod = Omit<Union, 'whatever'>; // DU gets broken
type UnionMod2 = OmitBetter<Union, 'a'>; // DU remains unchanged
type UnionMod3 = OmitBetter<Union, 'a'>; // DU is still a DU but without field 'a'
type UnionMod4 = OmitBetterStrict<Union, 'c'>; // DU is still a DU but without common field 'c'
type UnionMod5 = OmitBetterStrict<Union, 'a'>; // error, because 'a' is not a common field of DU

// regular Omit use-cases (they all work properly)
type Regular = Omit<{ readonly a: 'a'; b?: 'b'; c: 'c'; }, 'whatever' | 'c'>;
type Regular2 = OmitBetter<{ readonly a: 'a'; b?: 'b'; c: 'c'; }, 'whatever' | 'c'>;
type Regular3 = OmitBetterStrict<{ readonly a: 'a'; b?: 'b'; c: 'c'; }, 'c'>;

Expected behavior:
Omit type should properly omit fields from objects but discriminated unions should still be discriminated unions. The expected behaviour is observed when using Omit from type-zoo package. The same approach was also proposed by the Microsoft member here: #28791 (comment).

Actual behavior:
Built-in Omit type which is being introduced in TypeScript 3.5 "merges" discriminated unions. When omitting field c from

{ type: 'A', a: 'a', c: string } |
{ type: 'B', b: 'b', c: string }

the resulting type should be equivalent to

{ type: 'A', a: 'a' } |
{ type: 'B', b: 'b' }

but with Omit@3.5, we get

{ type: 'A' | 'B' }

which is no longer a discriminated union.

According to Design Meeting Notes, 4/15/2019 (#30947), the resolution about making Omit stricter was based on "not worth breaking half the usages of Omit in the wild". When looking at "type Omit" search results, some of them also use the conditional type trick to distribute Omit over discriminated union. Following the same "not breaking the usages in the wild" principle, it might be a better idea to change the built-in Omit into the version with T extends any ? ... : never. Especially since it does not break the regular use-cases.

Playground Link: Link

[dragomirtitian]

Pick isn't distributed either. Making all library types distributed can have severe performance implications. This was also discussed here: #28339

[RyanCavanaugh]

All possible definitions of Omit have certain trade-offs; we've chosen one we think is the best general fit and can't really change it at this point without inducing a large set of hard-to-pinpoint breaks.

[typescript-bot]

This issue has been marked 'Working as Intended' and has seen no recent activity. It has been automatically closed for house-keeping purposes.

[tantaman]

A workaround for this is to use mapped types.

E.g.,

type RemoveNameField<Type> = {
  [Property in keyof Type as Exclude<Property, "name">]: Type[Property];
};

instead of Omit<Type, 'name'>

TS Playground example based on #39556

[micdah]

Found another workaround by using the fact that T extends K is applied per-member of a union, so we can actually define a re-usable OmitUnion<T, K> type which can omit any number of members

interface Dog { type: 'dog', name: string, barks: boolean }
interface Cat { type: 'cat', name: string, meows: boolean }
type Pet = Dog | Cat

type PetWithoutName = Omit<Pet, 'name'>

// Cannot because PetWithoutName is reduced to {type: 'dog' | 'cat'}
let unnamedPet:PetWithoutName = { type: 'dog', barks: true }


type OmitUnion<T, K extends keyof any> = T extends any ? Omit<T, K> : never
// Uses the fact that `T extends K` is applied to _each union member_ of T in-turn

type PetWithoutName2 = OmitUnion<Pet, 'name'>
let unnamedPet2:PetWithoutName2 = { type: 'dog', barks: true }

So instead of ending up with the type { type: 'dog' | 'cat' } when applying Omit<Pet, 'name'> we instead want Omit<Dog, 'name'> | Omit<Cat, 'name'> which we can get by using T extends any which ensures we apply Omit<T, K>on each member of the union, rather than the entire union.

It's kind of a hack - but I like that it enables us to have a generic re-usable OmitUnion<T, K>

[unional]

@micdah yes, that is the way to get around it in type-zoo and type-plus

https://github.com/unional/type-plus/blob/main/packages/type-plus/src/object/omit.ts
https://github.com/pelotom/type-zoo/blob/master/types/index.d.ts#L26
#28339 (comment)