Closed
Description
Hi, thank you for PythonCall.jl
/juliacall
! I hope it's ok to just open an issue here.
When trying to import juliacall
on Apple M1 I am getting the following error:
Python 3.9.12 (main, Apr 5 2022, 01:52:34)
[Clang 12.0.0 ] :: Anaconda, Inc. on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> import juliacall
fatal: error thrown and no exception handler available.
ErrorException("could not load symbol "jl_n_threads":
dlsym(RTLD_DEFAULT, jl_n_threads): symbol not found")
ijl_errorf at /Applications/Julia-1.8.app/Contents/Resources/julia/lib/julia/libjulia-internal.1.8.dylib (unknown line)
ijl_dlsym at /Applications/Julia-1.8.app/Contents/Resources/julia/lib/julia/libjulia-internal.1.8.dylib (unknown line)
ijl_load_and_lookup at /Applications/Julia-1.8.app/Contents/Resources/julia/lib/julia/libjulia-internal.1.8.dylib (unknown line)
nthreads at ./threadingconstructs.jl:23 [inlined]
__preinit_threads__ at ./task.jl:706
jfptr___preinit_threads___40244 at /Applications/Julia-1.8.app/Contents/Resources/julia/lib/julia/sys.dylib (unknown line)
ijl_apply_generic at /Applications/Julia-1.8.app/Contents/Resources/julia/lib/julia/libjulia-internal.1.8.dylib (unknown line)
_finish_julia_init at /Applications/Julia-1.8.app/Contents/Resources/julia/lib/julia/libjulia-internal.1.8.dylib (unknown line)
julia_init at /Applications/Julia-1.8.app/Contents/Resources/julia/lib/julia/libjulia-internal.1.8.dylib (unknown line)
ijl_init at /Applications/Julia-1.8.app/Contents/Resources/julia/lib/julia/libjulia-internal.1.8.dylib (unknown line)
I would be really happy about any help with this. Thanks again! :)
Metadata
Metadata
Assignees
Labels
No labels