Should approach fastPowering this way?

[iAziz786]

While learning about Fast Powering Algorithm, I notice that a minor tweak can be made to the fastPowering.js file.

In both of the cases whether the power is odd or event, calculated multiplier will be the same. So, we can calculate multiplier before the if clause and return the multiplication based on the nature of power.

export default function fastPowering(base, power) {
  if (power === 0) {
    // Anything that is raised to the power of zero is 1.
    return 1;
  }

  // multiplier will be same whether power is even or odd
  const multiplier = fastPowering(base, Math.floor(power / 2)); 
  if (power % 2 === 0) {
    // If the power is even...
    // we may recursively redefine the result via twice smaller powers:
    // x^8 = x^4 * x^4.
    return multiplier * multiplier;
  }

  // If the power is odd...
  // we may recursively redefine the result via twice smaller powers:
  // x^9 = x^4 * x^4 * x.
  return multiplier * multiplier * base;
}

@trekhleb Let me know your thoughts. And if you're okay with this implementation I can raise a PR.