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e0020.py
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# -*- coding: utf-8 -*-
"""Valid Parentheses
Given a string containing just the characters '(', ')', '{', '}', '[' and ']',
determine if the input string is valid.
An input string is valid if:
Open brackets must be closed by the same type of brackets.
Open brackets must be closed in the correct order.
Note that an empty string is also considered valid.
Example 1:
Input: "()"
Output: true
Example 2:
Input: "()[]{}"
Output: true
Example 3:
Input: "(]"
Output: false
Example 4:
Input: "([)]"
Output: false
Example 5:
Input: "{[]}"
Output: true
"""
from collections import namedtuple
DataColl = namedtuple('DataColl', ('cate', 'head'))
alphabet = {
'(': DataColl(cate=1, head=True),
')': DataColl(cate=1, head=False),
'[': DataColl(cate=2, head=True),
']': DataColl(cate=2, head=False),
'{': DataColl(cate=3, head=True),
'}': DataColl(cate=3, head=False),
}
def is_valid(pattern: str) -> bool:
def match(ch: chr):
return alphabet[ch]
def helper(s: str, rec: str) -> bool:
# valid if empty string
if s == '' and rec == '':
return True
# invalid if open brackets not closed
elif s == '' and rec != '':
return False
# push heads to recursion arg
elif match(s[0]).head is True:
return helper(s[1:], s[0] + rec)
# decide if the bracket closing is valid
else:
if match(s[0]).cate != match(rec[0]).cate:
return False
else:
return helper(s[1:], rec[1:])
return helper(pattern, '')
if __name__ == '__main__':
in1 = '()'
in2 = '()[]{}'
in3 = '(]'
in4 = '([)]'
in5 = '{[]}'
in6 = ''
in7 = '(['
exp1 = True
exp2 = True
exp3 = False
exp4 = False
exp5 = True
exp6 = True
exp7 = False
assert is_valid(in1) == exp1
assert is_valid(in2) == exp2
assert is_valid(in3) == exp3
assert is_valid(in4) == exp4
assert is_valid(in5) == exp5
assert is_valid(in6) == exp6
assert is_valid(in7) == exp7