"""
I just bombed an interview and made pretty much zero
progress on my interview question.

Given a number, find the next higher number which has the
exact same set of digits as the original number.
For example: given 38276 return 38627.
             given 99999 return -1. (no such number exists)

Condensed mathematical description:

Find largest index i such that array[i − 1] < array[i].
(If no such i exists, then this is already the last permutation.)

Find largest index j such that j ≥ i and array[j] > array[i − 1].

Swap array[j] and array[i − 1].

Reverse the suffix starting at array[i].

"""
import unittest


def next_bigger(num):

    digits = [int(i) for i in str(num)]
    idx = len(digits) - 1

    while idx >= 1 and digits[idx-1] >= digits[idx]:
        idx -= 1

    if idx == 0:
        return -1  # no such number exists

    pivot = digits[idx-1]
    swap_idx = len(digits) - 1

    while pivot >= digits[swap_idx]:
        swap_idx -= 1

    digits[swap_idx], digits[idx-1] = digits[idx-1], digits[swap_idx]
    digits[idx:] = digits[:idx-1:-1]   # prefer slicing instead of reversed(digits[idx:])

    return int(''.join(str(x) for x in digits))


class TestSuite(unittest.TestCase):

    def test_next_bigger(self):

        self.assertEqual(next_bigger(38276), 38627)
        self.assertEqual(next_bigger(12345), 12354)
        self.assertEqual(next_bigger(1528452), 1528524)
        self.assertEqual(next_bigger(138654), 143568)

        self.assertEqual(next_bigger(54321), -1)
        self.assertEqual(next_bigger(999), -1)
        self.assertEqual(next_bigger(5), -1)


if __name__ == '__main__':

    unittest.main()